Write log4 14 as a logarithm of base 3.

1) (log4) 3 / (log14) 3

2) (log14) 3 / (log4) 3

3) (log3) 4 / (log3) 14

4) (log3) 14 / (log3) 4,

Question

Ella Day

Mathematics

2 December, 05:15

Write log4 14 as a logarithm of base 3.

1) (log4) 3 / (log14) 3

2) (log14) 3 / (log4) 3

3) (log3) 4 / (log3) 14

4) (log3) 14 / (log3) 4,

+3

Answers (1)

Know the Answer?

Sarahi Walls · Answer 1

The change-of-base formula for logarithms is:

loga (b) = [logc (b) ] / [logc (a) ]

where:

a = original base

b = original argument

c = new base

Hence,

log4 (14) = log3 (14) / log3 (4)

Therefore the correct answer is D.

Write log4 14 as a logarithm of base 3.1) (log4) 3 / (log14) 32) (log14) 3 / (log4) 33) (log3) 4 / (log3) 144) (log3) 14 / (log3) 4,

Write log4 14 as a logarithm of base 3.

1) (log4) 3 / (log14) 3

2) (log14) 3 / (log4) 3

3) (log3) 4 / (log3) 14

4) (log3) 14 / (log3) 4,