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20 January, 08:30

8. Factor 12y2 + 5y - 2 completely.

A. (6y - 1) (2y + 2)

B. (4y - 2) (3y + 1)

C. (4y - 1) (3y + 2)

D. (4y + 1) (3y - 2)

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Answers (2)
  1. 20 January, 08:32
    0
    C. (4y - 1) (3y+2)

    Step-by-step explanation:

    12 y^2 + 5 y - 2

    12 y^2 + (-3+8) y - 2

    12 y^2 - 3y + 8y - 2

    3y (4y-1) + 2 (4y-1)

    (4y-1) (3y+2)
  2. 20 January, 08:36
    0
    C is the correct answer because in order to factor it completely, you need to factor by grouping it
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