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Alonzo Delacruz
Mathematics
28 March, 22:59
Find the x and y intercepts for y=3x/x^2+9
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Bronson Pierce
28 March, 23:03
0
So ...
Y=3x / (x^2+9), plug in 0 for Y.
0=3x / (x^2+9), multiply both sides by denominator
0=3x, at y=, x=0. Intercept at origin (:
For
Y = (3x/x^2) + 9, plug in 0 for Y
0 = (3x/x^2) + 9, subtract both sides
-9 = (3x/x^2), divide by x on the right
-9=3/x, multiply by x to the other side
-9x=3, and divide by - 9
X=-1/3 or -.33333. At x = 0 is null, because it's division by 0 (: so no y Intercept
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Sienna Shaw
28 March, 23:26
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Plug in 0 for x. Plug in 0 for y.
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