Which is an equation of the line that has a

y-intercept of - 2 and is parallel to the line whose

equation is 4y = 3x + 7?

Answer: 4y = 3x - 8.

Step-by-step explanation:

From the equation of a line

y = mx + c, where m is the gradient and c is the y intercept.

From conditions for parallelism, for two lines to be parallel to each other, their gradients must be equal ie m1 = m2

Now since c = - 2, the equation of the new line parallel to

4y = 3x + 7 will be, you should then find m1_from the given equation

Therefore, m1 = 3/4 and since the two line are parallel to each other, m2 = 3/4

Substitute for m2 in the new equation giving c = - 2,

y = 3x/4 - 2

Multiply through by 4, the equation

4y = 3x - 8 which is the equation of the new line.