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1 March, 13:04

How do I solve (z+7) ^2=3

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  1. 1 March, 13:26
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    (z+7) ^2=3

    z^2+14z+46=0

    z={-14+-√ (14^2-4.1.46) }/2.1

    =-14+-√ (196-184) / 2

    =-14+-√12/2

    =-14+-2√3/2

    =-7+-√3

    so it is,

    z=-7+√3

    or,

    z=-7-√3
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