The product of two consecutive even integers is 840 find these numbers

Integers are 2n and 2n + 2

2n * (2n + 2) = 840

4n^2 + 4n - 840 = 0

Solving by quadratic formula:

n = 14 and n+2 = 16

Therefore the integers (2*n and 2*n+2) are

28 and 30

check:

28 * 30 = 840