Use a system of equations to solve this problem.

Bronze is a mix, or alloy, of tin and copper. A metal worker needs 100 g of bronze that is 25% tin. He has one tin/copper alloy that is 5% tin and another tin/copper alloy that is 45% tin.

Let x = the number of grams of the 5% tin alloy.

Let y = the number of grams of the 45% tin alloy.

How many grams of each alloy should the metal worker combine?

Enter your answers into the boxes.

g of the 5% tin alloy and g of the 45% tin alloy.

Question

Parker Winters

Mathematics

17 January, 09:28

Use a system of equations to solve this problem.

Bronze is a mix, or alloy, of tin and copper. A metal worker needs 100 g of bronze that is 25% tin. He has one tin/copper alloy that is 5% tin and another tin/copper alloy that is 45% tin.

Let x = the number of grams of the 5% tin alloy.

Let y = the number of grams of the 45% tin alloy.

How many grams of each alloy should the metal worker combine?

Enter your answers into the boxes.

g of the 5% tin alloy and g of the 45% tin alloy.

+4

Answers (1)

Know the Answer?

Gracelyn Skinner · Answer 1

Those are the two equations:

x+y=100

the sum of the weight of both alloys is 100 g

0.5x+0.45y=0.25*100

the sum of the weights of tin has to be 25% of 100g, which is actually 25 g

0.5x+0.45y=25

So we have:

x+y=100

0.5x+0.45y=25

x=10-y

0.5x+0.45y=25

We substitute:

0.5 (10-y) + 0.45y=25

We calculate:

5-0.5y+0.45y=25

-0.5y+0.45y=20

0.4y=20

4y=200

y=50

So he needs 50 grams of 45% alloy and 100-50=50 grams of tin alloy as well