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The equations for two lines in the coordinate plane are 2dx - y = - 4 and 4x - y = - 6, where d represents an unknown value. What value (s) of d would make these lines perpendicular?

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  1. 1 July, 07:03
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    First, let's put both lines in Slope-intercept form (y = mx + b) to make it a bit easier:

    Line A:

    2dx - y = - 4

    -y = - 4 - 2dx

    y = 2dx + 4

    Line B:

    4x - y = - 6

    -y = - 6 - 4x

    y = 4x + 6

    We want a value for d so that line A is perpendicular to line B, which has a slope of 4. That means that the slope of line A must equal - 1/4.

    2d = - 1/4

    d = - 1/8
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