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28 August, 13:10

A jar contains a combination of 60 nickels and dimes worth a total of $4.30. suppose that is deemed desirable to determine how many of each kind of coin are in the jar.

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  1. 28 August, 13:38
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    We will represent everything in cents

    nickles are worth 5 cents and dimes are 10 cents

    n=number of nickles

    d=number of dimes

    60 total coins

    n+d=60

    total is 430 cents

    5n+10d=430

    divide both sides by 5

    n+2d=86

    we gots

    n+d=60 and

    n+2d=86

    eliminate

    multiply first equation by - 1 and add to 2nd equation

    -n-d=-60

    n+2d=86 +

    0n+1d=26

    d=26

    so

    n+d=60

    n+26=60

    n=34

    34 nickles and 26 dimes
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