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Maximus
Mathematics
27 December, 17:18
What is the integral of y'sinx=ylny ... ?
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Parker Hinton
27 December, 17:42
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Y'sinx=ylny, is equivalent to dy / dx (sinx=ylny, and dy sinx=ylny dx
it is similar to dy / ylny = dx/sinx
so integral (dy/ylny = integral dx/sinx)
integral dx/sinx) = Ln{abs value (tan (x / 2 + pi / 4) }
integral (dy/ylny = ln (lny)
final answer is lny = {abs value (tan (x / 2 + pi / 4) }+C, you can find y, or x
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