What would be the value of p so that the quadratic equation px^2 - 4x + 1 = 0 has equal roots

p = 4

Step-by-step explanation:

Using the discriminant b² - 4ac to determine the nature of the roots.

If b² - 4ac = 0 then real and equal roots

Given

px² - 4x + 1 = 0

with a = p, b = - 4 and c = 1, then

( - 4) ² - 4p = 0

16 - 4p = 0 (subtract 16 from both sides)

- 4p = - 16 (divide both sides by - 4)

p = 4

for repeated roots,

b²-4ac=0

16-{4p}=0

p=4