An object is launched from the ground. The object's height, in feet, can be described by the quadratic function h (t) = 80t - 16t2, where t is the time, in seconds, since the object was launched. When will the object hit the ground after it is launched? Explain how you found your answer.

Question

8 January, 22:36

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Ruger · Answer 1

Set h (t), time = 0.

0 = 80t-16t^2

-16t^2+80t = 0

Factor

-16t (t-5) = 0

t = 0 (when launched)

& t = 5