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12 April, 16:36

Given the Arithmetic sequence A1, A2, A3, A4 44, 51, 58, 65 What is the value of A39?

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Answers (2)
  1. 12 April, 16:45
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    This is an arithmetic sequence because there is a common difference between terms, a constant found when subtracting the preceding term from any term in the sequence. In this case the common difference is 7.

    Any arithmetic sequence can be expressed as:

    a (n) = a+d (n-1), a=initial value, d=common difference, n=term number

    Here we have a=44 and d=7 so

    a (n) = 44+7 (n-1)

    a (n) = 44+7n-7

    a (n) = 7n+37, so the 39th term is:

    a (37) = 7 (37) + 7

    a (37) = 266

    I am assuming that 44 is the first term, not the 5th term ... if 44 was the fifth term let me know and I will edit to reflect that ...
  2. 12 April, 16:50
    0
    This is an arithmetic sequence because there is a common difference between terms, a constant found when subtracting the preceding term from any term in the sequence. In this case the common difference is 7.

    Any arithmetic sequence can be expressed as:

    a (n) = a+d (n-1), a=initial value, d=common difference, n=term number

    Here we have a=44 and d=7 so

    a (n) = 44+7 (n-1)

    a (n) = 44+7n-7

    a (n) = 7n+37, so the 39th term is:

    a (37) = 7 (37) + 7

    a (37) = 266

    I am assuming that 44 is the first term, not the 5th term ... if 44 was the fifth term let me know and I will edit to reflect that ...
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