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31 May, 08:31

Frank has twice as many CDs as Vanessa. Lois has 4 less than 2 times as many CDs as Frank. If there is a total of 115 CDs for all 3 people, how many CDs does each person have?

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  1. 31 May, 08:36
    0
    So Frank has 34 CDs, Vanessa has 17 CD's and Lois has 64 CDs

    Step-by-step explanation:

    Let's call the amount of CDs that Frank has by 'F', that Vanessa has by 'V' and that Lois has by 'L'. Then, we can write the following equations:

    F = 2*V

    L = 2*F - 4

    F + V + L = 115

    If we use the values of F and L in the third equation, we have that:

    2*V + V + 2 * (2*V) - 4 = 115

    7*V = 119

    V = 17 CD's

    Now we can find F:

    F = 2*V = 34 CDs

    And then we find L:

    L = 2*F - 4 = 68 - 4 = 64 CDs

    So Frank has 34 CDs, Vanessa has 17 CD's and Lois has 64 CDs
  2. 31 May, 08:53
    0
    Frank, Vanessa, Lois have 34, 17, 64 disks respectively

    Step-by-step explanation:

    In this question, we are to calculate the number of disks each of the 3 has.

    Let the number of disks owned by Frank be x

    for vanessa, she has half of what frank has and that would be x/2

    Lois has 4 less than 2 times what Frank has, that would be 2x - 4

    adding the 3, we have a total of 115 disks

    This means that;

    x + x/2 + (2x-4) = 115

    Multiply throughout by 2;

    that gives;

    2x + x + 4x - 8 = 230

    7x - 8 = 230

    7x = 230 + 8

    7x = 238

    x = 238/7

    x = 34 disks

    Frank has 34

    Vaness has 34/2 = 17

    Lois have 2x - 4 = 2 (34) - 4 = 68 - 4 = 64 disks
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