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1 March, 12:26

Factor the expression 6x^2 + 5x + 1

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Answers (2)
  1. 1 March, 12:51
    0
    (2x + 1) (3x + 1)

    Step-by-step explanation:

    Given

    6x² + 5x + 1

    Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x - term

    product = 6 * 1 = 6 and sum = + 5

    The factors are + 3 and + 2

    Use these factors to split the x0 term

    6x² + 3x + 2x + 1 (factor the first/second and third/fourth terms)

    = 3x (2x + 1) + 1 (2x + 1) ← factor out (2x + 1) from each term

    = (2x + 1) (3x + 1) ← in factored form
  2. 1 March, 12:55
    0
    The factors are (3x+1) (2x+1)

    Step-by-step explanation:

    The expression is:

    6x^2 + 5x + 1

    We have to break the middle term to find its factors. For this first we have to multiply the coefficient of 1st terms with the constant term:

    6*1 = 6

    Now we have to find any two numbers whose product is 6 and whose sum is the middle term:

    3*2=6

    3+2=5

    Now break the middle term by these two numbers.

    6x^2 + 5x + 1

    6x^2+3x+2x+1

    Group the first two terms and last two terms:

    (6x^2+3x) + (2x+1)

    Now take out common factor from each term:

    3x (2x+1) + 1 (2x+1)

    (3x+1) (2x+1)

    Therefore the factors are (3x+1) (2x+1) ...
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