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30 November, 10:47

A, B, and C are polynomials, where A = n, B = 2n + 6, and C = n2 - 1. What is AB - C in simplest form?

A=-n2 + 3n + 5

B=n2 + 6n + 1

C=2n2 + 6n - 1

D=3n2 + 5

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Answers (1)
  1. 30 November, 10:51
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    If you would like to find AB - C in simplest form, you can do this using the following steps:

    A = n

    B = 2n + 6

    C = n^2 - 1

    AB - C = n * (2n + 6) - (n^2 - 1) = 2n^2 + 6n - n^2 + 1 = n^2 + 6n + 1

    The correct result would be B=n2 + 6n + 1.
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