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Cherish Jarvis
Mathematics
15 September, 15:36
Factors of 3x^2y^2+6x^2+12y^2+24
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Diya Stanton
15 September, 15:51
0
Look for the GCF
GCF = 3
so we have
3 (x^2y^2 + 2x^2 + 4y^2 + 8) Factor by grouping:-
= 3[ x^2 (y^2 + 2) + 4 (y^2 + 2) ]
= 3 (x^2 + 4) (y^2 + 2)
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