Ask Question
4 January, 05:45

What is the distance between the zeros of the function defined by 6 (2x2+x-8) - 2x (2x-1)

+2
Answers (1)
  1. 4 January, 05:49
    0
    12x^2+x-8 - (4x^2-1)

    12x^2+x-8-4x^2+1

    8x^2 + x - 7 = 0

    8x^2 + 8x - 7x - 7 = 0

    8x (x + 1) - 7 (x + 1) = 0

    (8x - 7) (x + 1) = 0

    8x - 7 = 0

    x + 1 = 0

    x = 7/8 and x = - 1
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What is the distance between the zeros of the function defined by 6 (2x2+x-8) - 2x (2x-1) ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers