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11 March, 07:00

Provide the first six terms of the following sequence:

t1=81 tn=1/3tn-1

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  1. 11 March, 07:24
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    We get tne n-th term with: tn=1/3tn-1

    We know that the first term is t1=81, so 81=1/3t*1-1

    81=1/3t-1

    82=1/3t

    82*3t=1

    3t=1/82

    t=1/82*3=1/246

    The second term is: 1/

    2 * (1/246) * 2) - 1

    We get the third term by replacing n with 3 and so on ...
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