The increase in a person's body temperature T (t), above 98.6ºF, can be modeled by the function T (t) = (4t) / (t^2 + 1), where t represents time elapsed. What is the meaning of the horizontal asymptote for this function? The horizontal asymptote of y = 0 means that the person's temperature will approach 98.6ºF as time elapses. The horizontal asymptote of y = 0 means that the person's temperature will approach 0ºF as time elapses. The horizontal asymptote of y = 4 means that the person's temperature will approach 102.6ºF as time elapses. The horizontal asymptote of y = 4 means that the person's temperature will approach 4ºF as time elapses.

Question

Nero

Mathematics

6 June, 09:02

The increase in a person's body temperature T (t), above 98.6ºF, can be modeled by the function T (t) = (4t) / (t^2 + 1), where t represents time elapsed. What is the meaning of the horizontal asymptote for this function? The horizontal asymptote of y = 0 means that the person's temperature will approach 98.6ºF as time elapses. The horizontal asymptote of y = 0 means that the person's temperature will approach 0ºF as time elapses. The horizontal asymptote of y = 4 means that the person's temperature will approach 102.6ºF as time elapses. The horizontal asymptote of y = 4 means that the person's temperature will approach 4ºF as time elapses.

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Nevaeh Clarke · Answer 1

Horizontal asymptote is what happens to T (f) as t becomes extremely large (approaches infinity). The horizontal asymptote is the line which T (t) approaches as t goes to infinity, i. e. the line y=0. This means that the person's body temperature will approach 0ºF above 98.6ºF as t goes to infinity.

i. e. the person's body temperature will approach 98.6ºF as time lapses. The first option.