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Kamden Kerr
Mathematics
29 June, 16:31
how do ypu slove dis?
y^2 (q-4) - c (q - 4)
+2
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Perla Quinn
29 June, 16:42
0
y2 (q-4) - c (q-4) Final result : (q - 4) • (y2 - c)
Step by step solution : Step 1 : Equation at the end of step 1 : ((y2) • (q - 4)) - c • (q - 4) Step 2 : Equation at the end of step 2 : y2 • (q - 4) - c • (q - 4) Step 3 : Pulling out like terms:
3.1 Pull out q-4
After pulling out, we are left with:
(q-4) • (y2 * 1 + (c * (-1)))
Trying to factor as a Difference of Squares:
3.2 Factoring: y2-c
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : y2 is the square of y1
Check : c1 is not a square!
Ruling : Binomial can not be factored as the difference of two perfect squares
Final result : (q - 4) • (y2 - c)
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