Solve for y:

Y^2-2xy=1

y = x ±√ (x²+1)

Step-by-step explanation:

Rewrite to standard quadratic form, then use the quadratic formula.

... y² - 2xy - 1 = 0

... a=1, b=-2x, c=-1, so the quadratic formula

... y = (-b ±√ (b²-4ac)) / (2a)

can be filled in as ...

... y = - (-2x) ±√ ((-2x) ² - 4 (1) (-1))) / 2 (1))

... y = x ±√ (x² + 1)

For any given value of x, there are two possible values of y. This is not a function.