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11 July, 15:55

Given the equation of the line 3x + 2y = 12, find (1) the gradient of the line. (2) the coordinates of the y-intercept

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  1. 11 July, 15:57
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    1.

    Manipulate the equation into Slope-Intercept form: y = mx + b

    m represents the slope (aka gradient)

    3x + 2y = 12

    Subtract 3x from both sides: 2y = - 3x + 12

    Divide both sides by 2: y = (-3/2) x + 6

    The gradient is - 3/2

    2.

    y-intercept is found when x-0

    3x + 2y = 12

    3 (0) + 2y = 12

    2y = 12

    y = 6

    The coordinate of the y-intercept is (6,0)
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