During the eclipse on January 26, 2009, the moon's shadow traveled 14,500 kilometers and covered 0.9 percent of the surface area of Earth. Earth's surface area is about 512 million square kilometers. Suppose the area covered by the shadow was rectangular. What would be the width of such a rectangle? Round your answer to the nearest kilometer.

A: 318km

B: 350km

C: 3178km

D: 392km

Question

Alden Waller

Mathematics

11 February, 03:35

During the eclipse on January 26, 2009, the moon's shadow traveled 14,500 kilometers and covered 0.9 percent of the surface area of Earth. Earth's surface area is about 512 million square kilometers. Suppose the area covered by the shadow was rectangular. What would be the width of such a rectangle? Round your answer to the nearest kilometer.

A: 318km

B: 350km

C: 3178km

D: 392km

+5

Answers (1)

Know the Answer?

Reyna Cole · Answer 1

The area covered by the shadow is given by:

A = (512,000,000) * (0.9 / 100)

A = 4,608,000

Then, since the area is a rectangle we have:

A = (w) * (l)

Where,

w: width

l: long

Substituting we have:

4,608,000 = (w) * (14,500)

Clearing w we have:

w = (4,608,000) / (14,500)

w = 317.7931034

Round to the nearest kilometer:

w = 318 Km

Answer:

The width of such a rectangle would be:

A: 318km