Ask Question
11 December, 17:23

6th square root of 125x^3y^9z^6

+2
Answers (1)
  1. 11 December, 17:47
    0
    Irrational numbers are those numbers whose denominators and in square root forms. We can express the numbers in lowest terms by taking out divisible perfect square numbers out of the square root sign. In this case, the rules applicable is that the simplest forms are those forms in which the variables degree is less than to the nth root. The numbers inside the roots should be divisible to the nth power of a number.

    In this case, 125 is not divisible than any 6th root. The only other variable that can be 6th root is y^9 and x^6. hence the answer is

    yz 6th root of (125x^3y^3)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “6th square root of 125x^3y^9z^6 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers