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3 February, 15:59

One number is seven less than five times another. If their sum is decreased by four the result is one. Find the numbers

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  1. 3 February, 16:26
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    Let the number be Y.

    Y is seven

    less than 5 times another (let that other be X)

    Y=7-5X

    sum of both Y and X minus 4 gives one

    Y+X-4=1

    now solve both equations.
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