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Carly Branch
Mathematics
10 January, 07:44
4.9t^2-2.78t-1.15=0 what is the value of T
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Emmanuel Barton
10 January, 08:08
0
t = 139/490 + sqrt (75671) / 490 or t = 139/490 - sqrt (75671) / 490
Step-by-step explanation:
Solve for t:
4.9 t^2 - 2.78 t - 1.15 = 0
4.9 t^2 - 2.78 t - 1.15 = (49 t^2) / 10 - (139 t) / 50 - 23/20:
(49 t^2) / 10 - (139 t) / 50 - 23/20 = 0
Multiply both sides by 10/49:
t^2 - (139 t) / 245 - 23/98 = 0
Add 23/98 to both sides:
t^2 - (139 t) / 245 = 23/98
Add 19321/240100 to both sides:
t^2 - (139 t) / 245 + 19321/240100 = 75671/240100
Write the left hand side as a square:
(t - 139/490) ^2 = 75671/240100
Take the square root of both sides:
t - 139/490 = sqrt (75671) / 490 or t - 139/490 = - sqrt (75671) / 490
Add 139/490 to both sides:
t = 139/490 + sqrt (75671) / 490 or t - 139/490 = - sqrt (75671) / 490
Add 139/490 to both sides:
Answer: t = 139/490 + sqrt (75671) / 490 or t = 139/490 - sqrt (75671) / 490
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