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17 June, 04:55

Find the 14th term of the geometric sequence 10,-20,40, ...

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  1. 17 June, 05:03
    0
    The sequence is multiplying by - 2, so

    x = 10 * (-2) ^n

    x = 10 * (-2) ^14

    x = 10 * 16 384

    x = 163 840
  2. 17 June, 05:15
    0
    Obviously each term is multiplied by - 2

    an=a1 times r^ (n-1)

    a1=first term

    r=common ratio

    r=-2

    a1=10

    an=10 times (-2) ^ (n-1)

    n=14=14th term

    a14=10 times (-2) ^ (14-1)

    a14=10 times (-2) ^13

    a14=10 times - 8192

    a14=-81920

    it is - 81920
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