A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. If acceleration due to gravity is - 16 ft/s2, approximately how many seconds after the launch will the toy rocket reach the ground? h (t) = at2 + vt + h0 0.05 s 2.03 s 3.80 s 3.70 s

Question

Kimora Neal

Mathematics

Yesterday, 21:33

A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. If acceleration due to gravity is - 16 ft/s2, approximately how many seconds after the launch will the toy rocket reach the ground? h (t) = at2 + vt + h0 0.05 s 2.03 s 3.80 s 3.70 s

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Beatrice · Answer 1

H (t) = - 16t^2+60t+3

find the zero where t is positive

-16t^2+60t+3=0

t = (-1/32) {-60 + / - sqrt (3600+192); sqrt 3792=61.58

use negative root

t = (-1/32) (-121.58) = 3.80 sec