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Josie Schaefer
Mathematics
29 March, 14:27
What is the product? (y^2+3y+7) (8y^3+y+1)
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Vincent Freeman
29 March, 14:39
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Multiply each term of (y^2+3y+7) with the other 3 of (8y^3+y+1) and add them
=8y^5+24y^4+57y^3+4y^2+10y+7
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