Carlisle conducted an experiment to determine if the there is a difference in mean body temperature for men and women. He found that the mean body temperature for a sample of 100 men was 97.9 with a population standard deviation of 0.57 and the mean body temperature for a sample of 100 women was 98.6 with a population standard deviation of 0.55.

Assuming the population of body temperatures for men and women is normally distributed, calculate the 99% confidence interval and the margin of error for the mean body temperature for both men and women. Using complete sentences, explain what these confidence intervals mean in the context of the problem.

Question

Dalton Villarreal

Mathematics

1 May, 10:17

Carlisle conducted an experiment to determine if the there is a difference in mean body temperature for men and women. He found that the mean body temperature for a sample of 100 men was 97.9 with a population standard deviation of 0.57 and the mean body temperature for a sample of 100 women was 98.6 with a population standard deviation of 0.55.

Assuming the population of body temperatures for men and women is normally distributed, calculate the 99% confidence interval and the margin of error for the mean body temperature for both men and women. Using complete sentences, explain what these confidence intervals mean in the context of the problem.

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Caesar · Answer 1

X1 - X2 + / - t * sqrt (s1^2/n1 + s2^2/n2)

X1 = 97.9

X2 = 98.6

S1=.57

S2=.55

N1 and n2 = 100

T * = whatever you find in the t-table (use the degrees of freedom=198 and 99% Confidence)

If the interval contains only negative values men have lower body temp than women. Only positive values, women have lower body temp. Both positive and negative there is no difference