Two right triangles, ABD and ACD, were created from ABC by

constructing AD 1 CB.

Follow these steps to prove that sin (B) = sin (C)

1. For

ABD, sin (B) = 1

Since their corresponding angles are congruent and the corresponding sides are in proportion

Step-by-step explanation:

For ABD,

Sin (B) = (AD : AB) = 1

∴ AD = AB

and if AD = AB

⇒ AD = AC (since AD 1 CB).

From triangle ACD,

Sin (C) = (AD : AC)

Since AD = AC, Hence Sin (B) = Sin (C) = 1

Also From definition of similar triangles ABD and ACD are Similar (i. e their corresponding angles are congruent and the corresponding sides are in proportion)

1 is h/c

2 is c sin (b) = h

3 is h/b

4 is b sin (c) = h

5 is substitution

6 is bc

Step-by-step explanation:

right on edge 2020