Ask Question
28 March, 18:44

X^3-5x^2-2x+24 factorize

0
Answers (2)
  1. 28 March, 20:36
    0
    Answer: (x-2) (x-3) (x-4)

    Step-by-step explanation:

    Use the rational root theorem to get started, then factor the remaining quadratic to find:

    f (x) = x^3-5x^2-2x+24

    f (2) = (2) ^3-5 (2) ^2-2 (2) + 24

    f (2) = 0

    i. e 2 is a root of f (x)

    (x-2) is a factor

    Now by dividing x^3-5x^2-2x+24by (x-2),

    we get q (x) = x^2-7x+12

    Since, q (x) is also a factor of x^3-5x^2-2x+24

    Factorising x^2-7x+12

    (x-4) (x-3)

    So, all the factors of

    x^3-5x^2-2x+24 are (x-4), (x-3) and (x-2)
  2. 28 March, 20:40
    0
    (x + 2) (x - 3) (x - 4) = 0
Know the Answer?