28 March, 18:44
28 March, 20:36
Answer: (x-2) (x-3) (x-4)
Use the rational root theorem to get started, then factor the remaining quadratic to find:
f (x) = x^3-5x^2-2x+24
f (2) = (2) ^3-5 (2) ^2-2 (2) + 24
f (2) = 0
i. e 2 is a root of f (x)
(x-2) is a factor
Now by dividing x^3-5x^2-2x+24by (x-2),
we get q (x) = x^2-7x+12
Since, q (x) is also a factor of x^3-5x^2-2x+24
So, all the factors of
x^3-5x^2-2x+24 are (x-4), (x-3) and (x-2)
28 March, 20:40
(x + 2) (x - 3) (x - 4) = 0
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