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17 January, 13:34

A shipment contains 10 good and 4 defective bulbs. If three bulbs are selected without replacement, determine the probability the third is defective given the first two are good.

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  1. 17 January, 13:40
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    1/3

    Step-by-step explanation:

    Since you know the first two are good, they do not factor in. The only difference now is your total.

    You had a total of 14 bulbs, but two were removed and we know they're good.

    Now you have a total of 12 bulbs. 4 are still defective. Your probability of pulling a defective one is 4/12, or reduced, 1/3.
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