Ask Question
5 November, 13:39

A bag contains 2 red marbles, 3 green marbles, and 4 blue marbles.

If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be green and the second will be red?

+5
Answers (2)
  1. 5 November, 13:45
    0
    0.083333333333 or 8.3%

    Step-by-step explanation:

    3/9x2/8

    The second fractions has a demoninator of 8 bc u already took one from the bag and didnt return it
  2. 5 November, 13:57
    0
    1/12.

    Step-by-step explanation:

    There are a total of 9 marbles so

    Prob (drawing first a green) = 3/9.

    After drawing the green there are 8 marbles left in the bag, so:

    Prob (drawing a red) = 2/8.

    The required probability = 3/9 * 2/8

    = 1/3 * 1/4

    = 1/12.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A bag contains 2 red marbles, 3 green marbles, and 4 blue marbles. If we choose a marble, then another marble without putting the first one ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers