Solve and graph the absolute value inequality: |2x + 1| ≤ 5. number line with closed dots on - 3 and 2 with shading going in the opposite directions. number line with closed dots on - 3 and 2 with shading in between. number line with open dots on - 3 and 2 with shading in between. number line with closed dots on - 2 and 2 with shading in between.

Question

Justus Velez

Mathematics

26 February, 20:04

Solve and graph the absolute value inequality: |2x + 1| ≤ 5. number line with closed dots on - 3 and 2 with shading going in the opposite directions. number line with closed dots on - 3 and 2 with shading in between. number line with open dots on - 3 and 2 with shading in between. number line with closed dots on - 2 and 2 with shading in between.

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Answers (2)

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Ferguson · Answer 1

We are given with the inequality |2x + 1| ≤ 5 and asked to solve the equation. In this case, we take first the positive side, that is 2x + 1 ≤ 5. this is equal to 2x ≤ 4 or x ≤ 2. For the negative side, the equality is - 5 ≤ 2x + 1. This is equal to - 6 ≤ 2x or - 3 ≤ x. Hence the solution is - 3 ≤ x ≤ 2. The answer is B. closed dots on - 3 and 2 with shading in between. The equal in ≤ means closed dots.

Koba · Answer 2

After solving and graphing the absolute value inequality of the equation |2x + 1| ≤ 5, I’ve come up with the conclusion that the answer would be the second option or the number line with closed dots on - 3 and 2 with shading in between. I am hoping that this answer has satisfied your query about this specific question.