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16 January, 11:06

Find three consecutive interferes whose sum is 96

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  1. 16 January, 11:20
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    31, 32, 33

    Step-by-step explanation:

    x + x + 1 + x + 2 = 96

    3x + 3 = 96

    -3 - 3

    3x = 93

    /3 / 3

    x = 31

    31 is the first number, so since they're consecutive, the second two numbers are 32 and 33.
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