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Tabitha Clarke
Mathematics
20 March, 14:49
Factor by grouping.
12x^3-20x^2+3x-5
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Moochie
20 March, 14:53
0
12x³ - 20x² + 3x - 5
4x² (3x) - 4x² (5) + 1 (3x) - 1 (5)
4x² (3x - 5) + 1 (3x - 5)
(4x² + 1) (3x - 5)
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Arturo Rollins
20 March, 15:17
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First, group them in 2's (2 numbers per group)
and see which ones have the factors of each other
you want to group 12x^3 with 3x because 3 is a factor of 12
then you want to group - 20x^2 and - 5 together becuase 5 is a factor of 20 so
(12x^3+3x) + (-20x^2-5)
undistribute
(3x) (4x^2+1) + (-5) (4x^2+1)
revese distribute (ab+ac=a (b+c))
(3x-5) (4x^2+1)
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