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22 January, 19:17

A spring has a natural length of 25 meters. A force of 12 newtons is required to stretch the spring to a length of 30 meters. How much work is done to stretch the spring from it's natural length to 40 meters?

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  1. 22 January, 19:25
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    F = ks

    12 = k (15)

    12/15 = k

    integrating from 0 to 15

    12/15 sds

    12/15 x S squared / 2 from 0 to 15
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