All possible random samples of 200 middle managers are selected from a population for a study concerning their mean annual income. The population standard deviation is computed to be $2,248.5. What is the standard deviation of the sampling distribution of the means?

158.993

Step-by-step explanation:

We have to find the standard deviation of the sampling distribution of the means.

We are given that population standard deviation=σ=2248.5 and sample size=n=200.

Standard deviation of sampling distribution of means=σxbar=σ/√n

σxbar=2248.5/√200

σxbar=2248.5/14.1421

σxbar=158.993

Thus, the standard deviation of the sampling distribution of the means is $158.993.