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16 October, 22:20

Write the vector u as a sum of two orthogonal vectors, one of which is the vector projection of u onto v

u = (-8, - 8), v = (-1, 2)

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  1. 16 October, 22:33
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    U = (-8, - 8)

    v = (-1, 2)

    the magnitude of vector projection of u onto v =

    dot product of u and v over the magnitude of v = (u. v) / ll v ll

    ll v ll = √ (-1² + 2²) = √5

    u. v = (-8, - 8). (-1, 2) = - 8*-1+2*-8 = - 8

    ∴ (u. v) / ll v ll = - 8/√5

    ∴ the vector projection of u onto v = [ (u. v) / ll v ll] * [ v / ll v ll]

    = [-8/√5] * (-1,2) / √5 = (8/5, - 16/5)

    The other orthogonal component = u - (8/5, - 16/5)

    = (-8, - 8) - (8/5, - 16/5) = (-48/5, - 24/5)

    So, u as a sum of two orthogonal vectors will be

    u = (8/5, - 16/5) + (-48/5, - 24/5)
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