Solve each quadratic equation:

x^2 + 3x = 10

(What is X?)

X^2. + 3x - 10=0

Using the quadratic formula for

ax^2. + bx. + c=0

X = {-b+_ sqrt [ (b^2) - 4ac]} / 2a

X = (-3+7) / 2 = 4/2=2

X = (-3-7) / 2 = - 10/2 = - 5

Solutions are x=2 and x = - 5

To complete the square, add the square of half the x-coefficient.

... x^2 + 3x + 2.25 = 12.25

... (x + 1.5) ^2 = 3.5^2

... x + 1.5 = ±3.5

... x = - 1.5 ±3.5

... x = - 5 or 2

You can also solve this by factoring.

... x^2 + 3x - 10 = 0

... (x - 2) * (x + 5) = 0

... x = 2 or - 5