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19 January, 12:04

What are the zeros of the quadratic function f (x) = 2x2 + 16x - 9?

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  1. 19 January, 12:09
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    Use the quadratic formula

    a = 2 b = 16 c = - 9

    x = [-b + - sq root (b^2 - 4*a*c) ] / 2*a

    x = [-16 + - sq root (256 - 4*-18) ] / 4

    x = [-16 + - sq root (256 + 72) ] / 4

    x = (-16 + - 18.11) / 4

    x1 =.5275

    x2 = - 8.5275
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