Rewrite f (x) = x^2+6x-12 in vertex form, then state its vertex and axis of symmetry

Complete teh square

isolate x terms

y = (x^2+6x) - 12

take 1/2 of 6 and squaer it then add positive and negative inside parenthasees

6/2=3, 3^2-9

y = (x^2+6x+9-9) - 12

comlete the square

y = ((x+3) ^2-9) - 12

y = (x+3) ^2-9-12

y = (x+3) ^2-21

for

y = (x-h) ^2+k

vertex is (h, k)

axis of symmetry is x=h

given

y = (x - (-3)) ^2 + (-21)

vertex is (-3,-21)

axis of symmetry is x=-3