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3 August, 13:50

At 8:45 p. m., a jet is located 64 mi due east of a city. A second jet is located 57 mi due north of the city.

To the nearest tenth of a mile, what is the distance between the two jets?

Enter your answer as a decimal in the box.

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Answers (1)
  1. 3 August, 14:13
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    Use Pythagorean theorem. a^2+b^2=c^2.

    If you plot it out, these create a perfect triangle. a=57, b=64.

    57^2 = 3249. 64^2 = 4096. a^2+b^2 = 7345. Take the square root of 7345 which comes out to be 85.7 miles.
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