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29 April, 07:04

The square of a number exceeds that number by 12. What are the two possible solutions?

3 or - 4

3 or 4

-3 or 4

+2
Answers (2)
  1. 29 April, 07:06
    0
    X^2=x+12

    minus x+12 both sides

    x^2-x-12=0

    factor

    (x-3) (x+4) = 0

    set each to zero

    x-3=0

    x=3

    x+4=0

    x=-4

    x=3 or - 4

    answer is first one
  2. 29 April, 07:31
    0
    The square of a number exceeds that number by 12. What are the two possible solutions would e B i think
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