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14 April, 15:59

Given g (x) = x^2-7x+1/4 show that the least possible value of g (x) is - 12

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  1. 14 April, 16:02
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    The least vale of the function would be the vertex. To find the vertex first find the x value by using x = - b/2a

    x=7/2 or 3.5

    Now plug this in for x to find the y value.

    y = (7/2) ^2 - 7 (7/2) + (1/4)

    y = (49/4) - (49/2) + (1/4)

    y = (49/4) - (98/4) + (1/4)

    y = (-48/4)

    y = - 12

    The vertex is (3.5,-12)

    The minimum (or max) of a function is the y value of the vertex so the min value is - 12
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