Using the section of the graph shown, which of these potential roots of the function should you test first? f (x) = 2x3 - 9x2 - 6x + 40

Given the polynomial F (x) = 2x3-9x2-6x+40, the first potential roots are - 2, 4 and 5/2. Solving for the first root, we divide the given function by x+2 where the result is 2x2-13x+40. Since the given polynomial is divisible by x+2, therefore the first root is - 2. For the second and third roots of the function, we can solve it using the quadratic equation formula.