2 problems SHOW WORK

1. Use synthetic division to find the zeroes of the function f (x) = x^3+x^2+4x+4

2. Find the sum. Write your answer in simplest form. (x - 4) / (x^2 - 2x) + (4) / (x^2 - 4)

1st problem:

-1, 2i, - 2i

Set the function equal to 0 and divide for x

0=x^3+x^2+4x+4

Subtract 4 from both sides leaving you with

-4=x^3+x^2+4x

divide both sides by four

-4:4 = - 1

That is how you get - 1

you now have - 1=x^2+x^3+x

Solve for x buy finding the square roots of x^2, x^3 and subtracting x from both sides and you get 2i, - 2i

Your answer to number one is - 1, 2i, - 2i

Second problem:

Find the LCD to be able to add these first

The LCD of (x-4) / x^2-2x is

x (x-2)

That is the first side done

The second side's LCD is (x+2) (x-2)

Now you can add the two together

x (x-2) + (x+2) (x-2) =

Your answer in fraction form is

(x+4) / x (x+2)