Solve |2x + 1| = 10

{9/2, 11/2}

{-9/2, 9/2}

{-11/2, 9/2}

Question

Naima Walton

Mathematics

17 March, 02:43

Solve |2x + 1| = 10

{9/2, 11/2}

{-9/2, 9/2}

{-11/2, 9/2}

+3

Answers (1)

Know the Answer?

Jack Galloway · Answer 1

The answer is - 11/2, 9/2

Explanation

You have to rewrite the absolute value equation as two separate equations.

2x+1=10

2x+1=-10

Then you solve for X in each equation.

2x+1=10 would give you 9/2

2x+1=-10 would give you - 11/2

So your final solutions would be x1 = - 11/2 x2 = 9/2

Solve |2x + 1| = 10{9/2, 11/2}{-9/2, 9/2}{-11/2, 9/2}

Solve |2x + 1| = 10

{9/2, 11/2}

{-9/2, 9/2}

{-11/2, 9/2}